Basically, what we do in well-ordering is assume that a set of counter-examples to P(n) called C exists and that c is the smallest element of C. In the link I provided, P(n): 1 + 2 + 3 + ... + n = n(n + 1)/2
- Then, for all n < c (e.g. n = c - 1), P(n) holds, since the smallest value of n where P(n) is false is n = c.
- With this in mind, we show P(c - 1):
1 + 2 + 3 + ... + (c - 1) = c(c - 1)/2 - Then we modify P(c - 1) to be P(c) and show that P(c) is in fact, true:
1 + 2 + 3 + ... + (c - 1) + c = c(c - 1)/2 + c # add c to both sides
= (c^2 - c + 2c)/2
= (c^2 + c)/2
= c(c + 1)/2 # P(c + 1)! - But P(c) is suppose to be false, this is a contradiction!
- Then, P(c) should be true and there is no counter-example to P(n).
- Therefore for all n, P(n) holds.
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